# How do you factor #12c^2+23c-9#?

##### 1 Answer

Sep 23, 2016

#### Answer:

#### Explanation:

#12c^2+23c-9#

Use an AC method:

Find a pair of factors of

Since

Use this pair to split the middle term and factor by grouping:

#12c^2+23c-9 = (12c^2+27c)-(4c+9)#

#color(white)(12c^2+23c-9) = 3c(4c+9)-1(4c+9)#

#color(white)(12c^2+23c-9) = (3c-1)(4c+9)#