How do you factor $12x^2 + 5x - 2= 0$ ?

Question

5955 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-05-31T04:41:12

$y = 12x^2 + 5x - 2$ = (x - p)(x - q). Use the new AC Method

Convert y to $y' = x^2 + 5x - 24.$ = (x - p')(x - q')

Compose factor pair of (-24) -> (-2, 12)(-3, 8) OK

Then, p' = -3 and q' = 8.

Then $p = -3/12 = -1/4 and q = 8/12 = 2/3$

Factored form: $y = (x - 1/4)(x + 2/3) = (4x - 1)(3x + 2).$

Check by developing: $y = (12x^2 + 8x - 3x - 2).$ OK

How do you factor 12x^2 + 5x - 2= 012x^2 + 5x - 2= 0?