How do you factor #12x^2 - 8x +1#?
Break the trinomial into two binomials
The general form is
The C value is positive that means that both the binomial factors must the same either both positive or both negative
The coefficient in front of B is negative this means that both of the binomial factors must be negative.
The coefficient in front of B is 8 so the sum of the binomial factors must be 8
Possible factors of 12 are
12 + 1 = 13
6 + 2 = 8
3 + 4 = 7
The two factors must be -6 and -2 so