How do you factor #12x²-3x#?

1 Answer
Jan 19, 2017

#3x(4x-1)#

Explanation:

We have to find the combined #color(blue)"common factor"# of the 2 terms.

The factors of 12 are #1,2,color(red)(3),4,6,12#

The factors of 3 are #1,color(red)(3)#

Hence the common factor of 12 and 3 is #color(red)(3)#

#x^2=x xx color(magenta)(x)" and " x=1xxcolor(magenta)(x)#

Hence the common factor of #x^2" and " x" is " color(magenta)(x)#

The combined common factor of the 2 terms is 3x

#rArr12x^2-3x=3x(4x-1)#