How do you factor #12x^3y^2 - 18xy^4#?

1 Answer
Aug 7, 2016

Answer:

#6xy^2(2x^2-3y^2)#

Explanation:

By finding #color(blue)"common factors"# of the 2 terms of the expression.

• 12 and 18 have a #color(blue)"common factor"# of 6

#x^3" and " x " have a " color(blue)("common factor") " of "x#

#y^2 " and " y^4" have a " color(blue)("common factor")" of " y^2#

Hence the 'combined' #color(blue)("common factor") " is " 6xy^2 #

#rArr12x^3y^2-18xy^4=6xy^2(2x^2-3y^2)#