How do you factor 12xy+24xy^2+36xy^3?

Mar 16, 2018

See below

Explanation:

To factorise we must factor out the Highest Common Factor of each term.

Here the HCFs of each term is $12$ , $x$ and $y$.

$\therefore 12 x y + 24 x {y}^{2} + 36 x {y}^{3} = 12 x y \left(1 + 2 y + 3 {y}^{2}\right)$

When we expand it out we should get the same answer.

Mar 16, 2018

$12 x y \left(1 + y \left(2 + 3 y\right)\right)$

Explanation:

At first take 12xy common out so,

12xy(1+2y+3y^2)

and then for the second 2 terms

$12 x y \left(1 + y \left(2 + 3 y\right)\right)$