How do you factor #4x^2+x#?

2 Answers
May 31, 2018

Answer:

#x(4x+1)#

Explanation:

The key realization here is that both terms have an #x#, so we can factor that out. When we factor an #x# out, we are essentially dividing every term by #x#. We get

#x(color(blue)(4x+1))#

Since the blue term has no common factors, we can't factor this further.

Hope this helps!

May 31, 2018

Answer:

#x(4x+1)#

Explanation:

#"take out a "color(blue)"common factor "x#

#=x(4x+1)#