# How do you factor 14x^2y^3+5xy^3-9y^3?

Apr 6, 2018

${y}^{3} \left(14 {x}^{2} + 5 x - 9\right)$

Here's how I did it:

#### Explanation:

To factorize something, you have to find everything that all the expressions have in common. That means we need to find the GCF (Greatest Common Factor) of all expressions.

$14 {x}^{2} {y}^{3} + 5 x {y}^{3} - 9 {y}^{3}$

We can see that they all have ${y}^{3}$, meaning we can factor that out.

If we factor out ${y}^{3}$, what we have left over is:
$14 {x}^{2} + 5 x - 9$

So finally we write it like this:
${y}^{3} \left(14 {x}^{2} + 5 x - 9\right)$

Hope this helps!