Question

How do you factor `15abc^2 + 6a^2bc - 6ab + 3bc`?

Answer 1

Answer: `3abc(5c+2a) - 3b(2a+3c)`

1. See it as `x-y`
   `x=15abc^2+6a^2bc`
   `y=(6ab+3bc)`
   So, `(15abc^2+6a^2bc) - (6ab+3bc)`

2. Factorise the common factor, `(15abc^2+6a^2bc)= 3abc(5c+2a)`
   `(6ab+3bc)= 3b(2a+3c)`