# How do you factor #15v^2-19v-10#?

##### 1 Answer

#### Answer:

#### Explanation:

Given:

#15v^2-19v-10#

This has discriminant

#Delta = b^2-4ac#

where

That is:

#Delta = (color(blue)(-19))^2-4(color(blue)(15))(color(blue)(-10))#

#color(white)(Delta) = 361+600#

#color(white)(Delta) = 961#

#color(white)(Delta) = 31^2#

Since

Let's use an AC method.

Look for a pair of factors of

The pair

Use this pair to split the middle term and factor by grouping:

#15v^2-19v-10 = (15v^2-25v)+(6v-10)#

#color(white)(15v^2-19v-10) = 5v(3v-5)+2(3v-5)#

#color(white)(15v^2-19v-10) = (5v+2)(3v-5)#