How do you factor #15x^2-19x+6#?

1 Answer
Aug 5, 2015

Answer:

Factor #y = 15x^2 - 19x + 6#

Ans: (5x - 3)(3x - 2)

Explanation:

#y = 15x^2 - 19x + 6 =# 15(x - p)(x - q).
I use the new AC Method (Yahoo, Google Search)
Converted trinomial #y' = x^2 - 19x + 90 =# (x - p')(x - q')
Factor pairs of 90 -> ...(6, 15)(9, 10). This sum is 19 = -b. Then p' = -9 and q' = -10.
Then, #p = (p')/a = -9/15 = -3/5# and #q = -10/15 = -2/3.#

Factored form: #y = 15(x - 3/5)(x - 2/3) = (5x - 3)(3x - 2)#