# How do you factor 15x^3-9x^2-6x?

May 27, 2016

$3 x \left(x - 1\right) \left(5 x + 2\right)$

#### Explanation:

1) Find the GCF of $15 {x}^{3} - 9 {x}^{2} - 6 x$, which is $3 x$.
2) Factor out the GCF: $3 x \left(5 {x}^{2} - 3 x - 2\right)$
3) Factor the trinomial in the parenthesis.
$5 {x}^{2} - 3 x - 2$
$5 {x}^{2} + 2 x - 5 x - 2$
$x \left(5 x + 2\right)$ & $- 1 \left(5 x + 2\right)$
$\left(x - 1\right) \left(5 x + 2\right)$
4) Insert in the GCF in front: $3 x \left(x - 1\right) \left(5 x + 2\right)$