How do you factor $16 - 2x^3$ ?

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Answer 1 · 2018-04-08T20:27:59

The fully factored polynomial is $=-2(x-2)(x^2+2x+4)$ .

First, factor out the $2$ :

$color(white)=16-2x^3$

$=2(8-x^3)$

Then, use the difference of cubes factoring:

$=2(2^3-x^3)$

$=2(2-x)(2^2-2x+x^2)$

$=2(2-x)(4-2x+x^2)$

Lastly, reorder the factors so that $x$ is in the front of each one:

$=2(2-x)(x^2+2x+4)$

$=2(-x+2)(x^2+2x+4)$

$=2(-1*(x-2))(x^2+2x+4)$

$=-2(x-2)(x^2+2x+4)$

That's as factored as it gets. Hope this helped!

How do you factor 16 - 2x^316 - 2x^3?