How do you factor #169a^2b^2-16c^ 4#?

1 Answer
Jun 12, 2016

Answer:

#(13ab+4c^2)(13ab-4c^2)#

Explanation:

To factor #169a^2b^2-16c^4# we must first recognize that this is the difference (subtraction) of two perfect squares.

#169a^2b^2 = (13ab)(13ab)#
#16c^4=(4c^2)(4c^2)#

When we factors the difference of two squares the binomials always have one #+# and one #-#.

#(13ab+4c^2)(13ab-4c^2)#