How do you factor $16a^2-121$ ?

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Answer 1 · 2018-04-13T00:07:23

$(4a+11)(4a-11)$

This can be factored using difference of squares. Both terms are perfect squares.

$a^2-b^2=(a+b)(a-b)$

First, let's find the square root of each term.

$sqrt(16a^2)=4a$

$sqrt121=11$

$(4a+11)(4a-11)$

How do you factor 16a^2-12116a^2-121?