# How do you factor 16a^2-121?

Apr 13, 2018

$\left(4 a + 11\right) \left(4 a - 11\right)$

#### Explanation:

This can be factored using difference of squares. Both terms are perfect squares.

${a}^{2} - {b}^{2} = \left(a + b\right) \left(a - b\right)$

First, let's find the square root of each term.

$\sqrt{16 {a}^{2}} = 4 a$

$\sqrt{121} = 11$

$\left(4 a + 11\right) \left(4 a - 11\right)$