How do you factor 16n^2-25?

$\left(4 n - 5\right) \left(4 n + 5\right)$
To eliminate the $n$ term in a quadratic equation the coefficients for $n$ in the factored for must be the same and the constants must be the same. Therefore:
$16 {n}^{2} - 25 \implies$
$\left(4 n - 5\right) \left(4 n + 5\right)$