# How do you factor 16x^2 + 32x + 7 = 0?

$f \left(x\right) = 16 {x}^{2} + 32 x + 7$= 16(x - p)(x - q). I use the new AC Method.
Convert f(x) to$f ' \left(x\right) = {x}^{2} + 32 x + 112 =$ (x - p')(x - q').
back to f(x), $p = \frac{p '}{a} = \frac{4}{16} = \frac{1}{4}$, and $q = \frac{q '}{a} = \frac{28}{16} = \frac{7}{4.}$
Factored form:$f \left(x\right) = 16 \left(x + \frac{1}{4}\right) \left(x + \frac{7}{4}\right) = \left(4 x + 1\right) \left(4 x + 7\right)$