# How do you factor x^3+64?

Feb 2, 2015

The answer is: ${x}^{3} + 64 = \left(x + 4\right) \left({x}^{2} - 4 x + 16\right)$.

It's easy if we remember the formula of sum of cubes, that says:

${x}^{3} + {y}^{3} = \left(x + y\right) \left({x}^{2} - x y + {y}^{2}\right)$.

In this case $64 = {4}^{3}$.

It's also to remember the formula of difference of cubes, that says:

${x}^{3} - {y}^{3} = \left(x - y\right) \left({x}^{2} + x y + {y}^{2}\right)$.