How do you factor $16x^2 -40x +25$ ?

Question

11576 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-22T16:07:20

$(4x-5)( 4x-5)=(4x-5)^2$

This is a pretty straight forward question.

We know that $color(red)((a-b)^2=a^2-2ab+b^2)$

Compare $a^2-2ab+b^2$ to $16x^2-40x+25$

Lets look at $a^2$ and $b^2$

$a^2=16x^2$ and $b^2=25$

$=>a=4x$ and $b=5$

Then, $2ab=2xx4x xx5 = 40x$ , as given in the expression.

Therefore,

$16x^2-40x+25$

$=(4x)^2 - (2 xx 4x xx5) + 5^2$

$=(4x-5)^2$

The factors are $4x-5, 4x-5$

How do you factor 16x^2 -40x +2516x^2 -40x +25?