# How do you factor #16x^2-x^2y^4#?

##### 1 Answer

May 12, 2016

#### Explanation:

First, notice that both terms have a common factor of

#16x^2-x^2y^4=x^2(16-y^4)#

Focusing on just the

#16=4^2# #y^4=(y^2)^2#

This will be useful since

#x^2(16-y^4)=x^2(4^2-(y^2)^2)=x^2(4+y^2)(4-y^2)#

Note that

#x^2(4+y^2)(4-y^2)=x^2(4+y^2)(2^2-y^2)=x^2(4+y^2)(2+y)(2-y)#