# How do you factor 16x^3 - 28x^2 - 30x?

$y = 2 x \left(8 {x}^{2} - 14 x - 15\right)$
Factor $\left(8 {x}^{2} - 14 x - 15\right)$ = (x - p)(x - q).
Converted trinomial: $\left({x}^{2} - 14 x - 120\right)$ = (x - p')(x - q').
Then,$p = \frac{p '}{a} = \frac{6}{8} = \frac{3}{4}$ and $q = \frac{q '}{a} = - \frac{20}{8} = - \frac{5}{2.}$
Finally: y = 2x(x + 3/4)(x - 5/2) = 2x(4x + 3)(2x - 5))