# How do you factor 16x^3 + 54?

In general ${a}^{3} + {b}^{3} = \left(a + b\right) \left({a}^{2} - a b + {b}^{2}\right)$
$16 {x}^{3} + 54$
$= 2 \left({\left(2 x\right)}^{3} + {\left(3\right)}^{3}\right)$
$= 2 \left(2 x + 3\right) \left(4 {x}^{2} - 6 x + 9\right)$