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How do you factor $16 y^{2} - 49$ $16y^2-49$ ?

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Konstantinos Michailidis

Jan 5, 2016

It is

$16 y^{2} - 49 = {(4 y)}^{2} - 7^{2} = (4 y + 7) (4 y - 7)$ $16y^2-49=(4y)^2-7^2=(4y+7)(4y-7)$

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