How do you factor #18b^2+15bd+2d^2#?
(6b + d)(3b + 2d)
Consider b as variable and d as a constant, and factor the trinomial by the new AC Method (Socratic Search)
Find p' and q' that have same sign (ac > 0).
Compose factor pairs of (ac = 36d^2) --> (2d, 18d)(3d, 12d). This last sum is (3d + 12d = 15d = b). Then p' = 3d and q' = 12d.
Back to y, we get: