How do you factor #18x^2-27x+4#?
One technique is to employ this handy formula:
You will get;
I recommend this technique for large coefficients of
1 and 18, 2 and 9, 6 and 3.
This will save you the time from trial and error especially for even bigger coefficients.
Ans: (6x - 1)(3x - 4)
Use the new AC Method. y = 18(x - p)(x - q)
p' and q' have same sign.
Factor pairs of (72) --> (2, 36)(3, 24) . This sum is 27 = -b.
Change the sum to b. Then, p' = -3 and q' = -24.