# How do you factor #192^3 - 3y^3#?

##### 1 Answer

May 13, 2015

Supposing 192³ - 3y³ equals 0,

3 x

Number 3 is multiplying both

3(

Just for curiosity's sake, we can solve this for y: pass the 3 to the other side, dividing zero, which will obviously end up equaling zero. Then, we'd have left

64 = y³

y = 4.

:)