How do you factor #192^3 - 3y^3#?
Supposing 192³ - 3y³ equals 0,
Number 3 is multiplying both
Just for curiosity's sake, we can solve this for y: pass the 3 to the other side, dividing zero, which will obviously end up equaling zero. Then, we'd have left
64 = y³
y = 4.