How do you factor #2(x - 2y)^2 - 4x(x - 2y)#?

1 Answer
Nov 27, 2015

Answer:

#-2(x^2-4y^2)#

Explanation:

#(x-2y) # common to both so:

#(x-2y)( 2(x-2y)-4x)#

Giving:
#(x-2y)(2x-4y-4x)#

#(x-2y)(-2x-4y)#

#-2color(white)(.) #is a common factor in #(-2x-4y)#

#(x-2y)(-2)(x+2y)#

#-2(x-2y)(x+2y)#

Consider standard form #a^2-b^2=(a-b)(a+b)#

So we now have:

#-2(x^2-4y^2)#