How do you factor #2(x - 2y)^2 - 4x(x - 2y)#?

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Answer 1 · 2015-11-27T14:05:08

#-2(x^2-4y^2)#

#(x-2y) # common to both so:

#(x-2y)( 2(x-2y)-4x)#

Giving:
#(x-2y)(2x-4y-4x)#

#(x-2y)(-2x-4y)#

#-2color(white)(.) #is a common factor in #(-2x-4y)#

#(x-2y)(-2)(x+2y)#

#-2(x-2y)(x+2y)#

Consider standard form #a^2-b^2=(a-b)(a+b)#

So we now have:

#-2(x^2-4y^2)#