How do you factor $2(x - 2y)^2 - 4x(x - 2y)$ ?

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Answer 1 · 2015-11-27T14:05:08

$-2(x^2-4y^2)$

$(x-2y)$ common to both so:

$(x-2y)( 2(x-2y)-4x)$

Giving:
$(x-2y)(2x-4y-4x)$

$(x-2y)(-2x-4y)$

$-2color(white)(.)$ is a common factor in $(-2x-4y)$

$(x-2y)(-2)(x+2y)$

$-2(x-2y)(x+2y)$

Consider standard form $a^2-b^2=(a-b)(a+b)$

So we now have:

$-2(x^2-4y^2)$

How do you factor 2(x - 2y)^2 - 4x(x - 2y)2(x - 2y)^2 - 4x(x - 2y)?