# How do you factor 200m^4 + 80m^3 + 8m^2?

Mar 22, 2016

$8 {m}^{2} {\left(5 m + 1\right)}^{2}$

#### Explanation:

In order to factor $200 {m}^{4} + 80 {m}^{3} + 8 {m}^{2}$

We begin be taking a common factor from each term
in this case $8 {m}^{2}$ will go in to each term.

$8 {m}^{2} \left(25 {m}^{2} + 10 m + 1\right)$

We can now factor the trinomial using the factors of the first and third term.
$25 {m}^{2}$ factors to $\left(5 m\right) \left(5 m\right)$
$1$ factors to $\left(1\right) \left(1\right)$

$8 {m}^{2} \left(5 m + 1\right) \left(5 m + 1\right)$

$8 {m}^{2} {\left(5 m + 1\right)}^{2}$