How do you factor #20x^2 + 37x + 15 #?
Use the quadratic formula to find the roots of
This is of the form
This has determinant
Since this is a perfect square,
Since we have gone to the trouble of computing the determinant, we might as well use the quadratic formula to find the roots of
Use a version of the AC Method to find:
Look for a factorization of
Note that one of
Next, for each of the pairs
Factor y = 20x^2 + 37x + 15
Ans: (5x + 3)(4x + 5)
I use the new AC Method to factor trinomials.
Factor pairs of (300) -> ...(6, 50)(10, 30)(12, 25). This sum is 35 = b.
Then, p' = 12, and q' = 25.