How do you factor # 21 - 4x - x^2#?

2 Answers
Mar 23, 2018

The factored quadratic is #-(x-3)(x+7)#.

Explanation:

First, factor out a #-1# so that the #x^2# term is positive (and also first):

#color(white)=21-4x-x^2#

#=-(-21+4x+x^2)#

#=-(x^2+4x-21)#

Now, we have to find two numbers that multiply to #-21# and add up to #4#. These numbers are #7# and #-3#. Split up the #x# term into these numbers, then factor them separately and combine later:

#=-(x^2+7x-3x-21)#

#=-(color(red)x(x+7)-3x-21)#

#=-(color(red)x(x+7)-color(blue)3(x+7))#

#=-((color(red)x-color(blue)3)(x+7))#

#=-(color(red)x-color(blue)3)(x+7)#

That's the factored quadratic. Hope this helped!

Mar 23, 2018

-(x - 3)(x + 7)

Explanation:

#y = -x^2 - 4x + 21#
#y = - (x^2 + 4x - 21)#
Find 2 numbers knowing the sum (b = 4) and the product (c = -21).
They are -3 and 7.
Factored form:
#y = - (x - 3)(x + 7)#