How do you factor #216x^3+1#?

1 Answer
Mar 24, 2017

Answer:

#(6x+1)(36x^2-6x+1)#

Explanation:

This is a #color(blue)"sum of cubes"# which is factorised, in general, as

#color(red)(bar(ul(|color(white)(2/2)color(black)(a^3+b^3=(a+b)(a^2-ab+b^2))color(white)(2/2)|)))#

#216x^3+1=(6x)^3+1^3#

#rArra=6x" and " b=1#

#rArr216x^3+1=(6x+1)(36x^2-6x+1)#