How do you factor 21m^2 - 57m + 30?

1 Answer
Jun 16, 2015

Factor: y = 21m^2 - 57m + 30

Explanation:

y = 3(7m^2 - 19m + 10)

To factor the trinomial in parentheses, i use the new AC Method (Google, Yahoo Search)
Converted trinomial: m^2 - 19m + 70. Roots have same sign. Compose factor pairs of a.c = 70 -> (2, 35)(5, 14). This sum is 19 = -b.
Then, p' = -5 and q' = -14. Next, p = -5/7 and q = -14/7 = -2.

Factored form: y = 3(7m - 5)(m - 2)