# How do you factor 24c^3t^2+26c^2t^3+6ct^4?

$2 c {t}^{2} \left(3 c + t\right) \left(4 c + 3 t\right)$
$24 {c}^{3} {t}^{2} + 26 {c}^{2} {t}^{3} + 6 c {t}^{4} = 2 c {t}^{2} \left(12 {c}^{2} + 13 c t + 3 {t}^{2}\right) = 2 c {t}^{2} \left(12 {c}^{2} + 9 c t + 4 c t + 3 {t}^{2}\right) = 2 c {t}^{2} \left(3 c \left(4 c + 3 t\right) + t \left(4 c + 3 t\right)\right) = 2 c {t}^{2} \left(3 c + t\right) \left(4 c + 3 t\right)$[Ans]