How do you factor $24 m^{2} - 32 m + 8$ $24m^2-32m+8$ ?

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Answer 1 · 2016-09-02T22:43:08

$8 (3 m - 1) (m - 1)$ $8(3m-1)(m-1)$

Always look for a common factor first.

$24 m^{2} - 32 m + 8$ $24m^2 - 32m +8$

= $8 (3 m^{2} - 4 m + 1)$ $8(3m^2 -4m +1)$

Find factors of 3 and 1 which add up to 4.
Signs are both negative.

= $8 (3 m - 1) (m - 1)$ $8(3m-1)(m-1)$

How do you factor 24m2−32m+824m^2-32m+8?