How do you factor #27m^3+1#?
This is a
#color(blue)"sum of cubes"#and is factorised in general as follows.
#27m^3=(3m)^3" and " 1=(1)^3rArra=3m" and " b=1#
Substituting these values gives required factors.
Using the formula for the sum of cubes.
We can use the formula for the sum of cubes
here our cubes are
The roots of
then are both complex. This means that the quadratic part cannot be factorized more with real numbers. We can write the irreducible factorization in complex numbers as