# How do you factor 27x^3 +1?

Use the identity: ${a}^{3} + {b}^{3} = \left(a + b\right) \left({a}^{2} - a b + {b}^{2}\right)$
$27 {x}^{3} + {1}^{3} = \left(3 x + 1\right) \left(9 {x}^{2} - 3 x + 1\right)$