# How do you factor 27x^3-8y^3?

$27 {x}^{3} - 8 {y}^{3} = \left(3 x - 2 y\right) \left(9 {x}^{2} + 6 x y + 4 {y}^{2}\right)$
$27 {x}^{3} - 8 {y}^{3} = {3}^{3} {x}^{3} - {2}^{3} {y}^{3}$
${a}^{3} - {b}^{3} = \left(a - b\right) \left({a}^{2} + a b + {b}^{2}\right)$
$3 x = a \text{ } 2 y = b$
$27 {x}^{3} - 8 {y}^{3} = \left(3 x - 2 y\right) \left(9 {x}^{2} + 6 x y + 4 {y}^{2}\right)$