# How do you factor 27x^3 -8y^3?

Sep 2, 2016

$\left(3 x - 2 y\right) \left(9 {y}^{2} + 6 x y + 4 {y}^{2}\right)$

#### Explanation:

We should notice that every part of this expression is a cube.
We can factor it as the difference of cubes.

$27 {x}^{3} - 8 {y}^{3}$

=$\left(3 x - 2 y\right) \left(9 {y}^{2} + 6 x y + 4 {y}^{2}\right)$