# How do you factor #2mx+4bx+3my+6by#?

##### 1 Answer

Oct 13, 2015

#### Explanation:

Your starting expression looks like this

#2mx + 4bx + 3my + 6by#

If you look at the coefficients, you'll notice that you have more than one option for *common factors*. Moreover, the

So, here's one way in which you can factor this expression. Use

#m * (2x + 3y) + 2b * (2x + 3y)#

#(2x + 3y) * (m + 2b)#

Alternatively, you can use

#2x * (m + 2b) + 3y * (m + 2b)#

#(m + 2b) * (2x + 3y)#