How do you factor #2mx+4bx+3my+6by#?

1 Answer
Oct 13, 2015

Answer:

#(m + 2b)(2x + 3y)#

Explanation:

Your starting expression looks like this

#2mx + 4bx + 3my + 6by#

If you look at the coefficients, you'll notice that you have more than one option for common factors. Moreover, the #m# and #b# terms can also be grouped together and used as common factors.

So, here's one way in which you can factor this expression. Use #m# and #2b# as common factors

#m * (2x + 3y) + 2b * (2x + 3y)#

#(2x + 3y) * (m + 2b)#

Alternatively, you can use #2x# and #3y# a common factors

#2x * (m + 2b) + 3y * (m + 2b)#

#(m + 2b) * (2x + 3y)#