# How do you factor #2n^2 + 6n - 108?

$2 {n}^{2} + 6 n - 108$
$= 2 \left({n}^{2} + 3 n - 54\right)$
Factoring $54$ as $2 \times 3 \times 3 \times 3$
and looking for a combination whose difference is $3$
$= 2 \left(n + 9\right) \left(n - 6\right)$