# How do you factor #2n^2+n-6#?

##### 1 Answer

Jul 21, 2016

#### Answer:

(2n - 3)(n + 2)

#### Explanation:

Use the new AC method (Socratic Search)

Find 2 numbers knowing sum (1) and product (- 12). They make the factor pair (-3, 4).

Back to trinomial y, p = -3/2 and q = 4/2 = 2

Factored form of y:

y = 2(n - 3/2)(n + 2) = (2n - 3)(n + 2)