How do you factor $2v^2 + 11v + 5$ ?

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Answer 1 · 2015-05-30T17:55:06

$2v^2+11v+5$

$= 2v^2+v+10v+5$

$=(2v^2+v)+(10v+5)$

$=v(2v+1)+5(2v+1)$

$=(v+5)(2v+1)$

How did I know to split the middle term into $v + 10v$ ?

I used a variant of the AC Method:

$A=2$ , $B=11$ , $C=5$ are the coefficients of the quadratic.

Look for a pair of factors of $AC=10$ whose sum is $B=11$ .

$1 xx 10 = 10$ and $1 + 10 = 11$

How do you factor 2v^2 + 11v + 52v^2 + 11v + 5?