How do you factor $2x³+16x²+24x$ ?

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Answer 1 · 2015-11-19T23:24:23

Separate out the common factor $2x$ , then find a pair of numbers whose sum is $8$ and whose product is $12$ to get:

$2x^3+16x^2+24x = 2x(x+2)(x+6)$

Notice that all of the terms are divisible by $2x$ , so separate that factor out first, Then notice that $2+6 = 8$ and $2xx6 = 12$ , so:

$2x^3+16x^2+24x = 2x(x^2+8x+12) = 2x(x+2)(x+6)$

How do you factor 2x³+16x²+24x2x³+16x²+24x?