How do you factor #2x³+16x²+24x#?

1 Answer
Nov 19, 2015

Answer:

Separate out the common factor #2x#, then find a pair of numbers whose sum is #8# and whose product is #12# to get:

#2x^3+16x^2+24x = 2x(x+2)(x+6)#

Explanation:

Notice that all of the terms are divisible by #2x#, so separate that factor out first, Then notice that #2+6 = 8# and #2xx6 = 12#, so:

#2x^3+16x^2+24x = 2x(x^2+8x+12) = 2x(x+2)(x+6)#