# How do you factor 2x^2+11x-6?

May 25, 2015

You can find its roots and then turn them into factors.

Let's use Bhaskara to find them.

$\frac{- 11 \pm \sqrt{121 - 4 \left(2\right) \left(- 6\right)}}{4}$
$\frac{- 11 \pm 13}{4}$
${x}_{1} = \frac{1}{2}$, which is the same as the factor $\left(2 x - 1\right) = 0$
${x}_{2} = - 6$, which is the same as the factor $\left(x + 6\right) = 0$

Thus,

$2 {x}^{2} + 11 x - 6 = \left(2 x - 1\right) \left(x + 6\right)$