How do you factor #2x^2+5x-3#?
1 Answer
Feb 21, 2017
Explanation:
The standard form of the
#color(blue)"quadratic function"# is.
#y=ax^2+bx+c# To factorise the function.
• consider the factors of the product ac which sum to give b
#"for "2x^2+5x-3#
#a=2, b=5" and "c=-3#
#rArrac=2xx-3=-6#
#"the required factors of -6 are "+6" and "-1#
#"Since " 6xx-1=-6" and " +6-1=+5#
#"now express " 2x^2+5x-3" as"#
#2x^2color(red)(+6x-x)-3# Factorise by 'grouping'
#rArr2x(x+3)-1(x+3)# Take out
#color(blue)"common factor " "of " (x+3)#
#rArr(x+3)(2x-1)larr" in factorised form"#