# How do you factor #2x^2+5x-6#?

##### 1 Answer

#### Answer:

#### Explanation:

Quadratic formula states that for an equation of the form

#x=(-b+sqrt(b^2-4ac))/(2a), (-b-sqrt(b^2-4ac))/(2a)# .

These two numbers are called roots.

Since plugging these 2 roots to

Thus, finding these roots means factoring the equation!

In this problem,

So

#x_1=(-5+sqrt(5^2-4(2)(-6)))/(2(2))# ,#x_2=(-5-sqrt(5^2-4(2)(-6)))/(2(2))# .

#x_1=(-5+sqrt(73))/(4)# ,#x_2=(-5-sqrt(73))/(4)# .

In conclusion,

#2x^2+5x-6=2(x+5/4-sqrt(73)/4)(x+5/4+sqrt(73)/4)# .

I multiplied the whole factored equation by 2 because the factored equation starts with