How do you factor $2x^2 -7x +3$ ?

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Answer 1 · 2015-11-08T18:51:57

$2x^2-7x+3=(2x-1)(x-3)$

$2x^2-7x+3$ is a quadratic equation, $ax^2+bx+c$ , where $a=2, b=-7, and c=3$ .

Use the $a*c$ method to factor this equation (also called splitting the middle).

Multiply $a$ times $c$ .

$2xx3=6$

Determine two numbers that when added equal $-7$ and when multiplied equal $6$ . The numbers $-x$ and $-6$ fit the criteria.

Rewrite the equation substituting $-x$ and $-6x$ for $-7x$ .

$2x^2-x-6x+3=$

$x(2x-1)-3(2x-1)$

Factor out the common term $(2x-1)$

$(2x-1)(x-3)$

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