How do you factor #2x^2-7x+6#?

1 Answer
Mar 27, 2016

Answer:

(2x - 3)(x - 2)

Explanation:

Use the new AC Method (Socratic Search)
#y = 2x^2 - 7x + 6 = #2(x + p)(x + q)
Converted #y' = x^2 - 7x + 12 =#(x + p')(x + q')
Find p' and q', knowing sum (-7) and product (12). We get: p' = -3 and q' = -4.
Therefor: p = (p')/a = -3/2 and q = (q')/a = -4/2 = -2.
Factor form: y = 2(x - 3/2)(x - 2) = (2x - 3)(x - 2)