How do you factor #2x^2+9x-5?

1 Answer
Alan P.
May 5, 2015

2x^2+9x-5

Hoping for an integer factoring, we look for factors of 2 and factors of 5 which when cross multiplied then subtracted give 9
(we know we need to subtract since the final term (5) is negative).

Fortunately there are not a lot of possible options for the factors and we soon come up with

{: (,2,xx,5,=,10),(,1,xx,-1,=-,1),(,,,,,9):}

So the factors of 2x^2+9x-5
are (2x-1)(x+5)

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