How do you factor ${(2 x)}^{3} + 1$ $(2x)^3 + 1$ ?

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Answer 1 · 2018-05-03T22:10:01

$8 x^{3} + 1$ $8x^3+1$

Apply exponent rule
$= 2^{3} x^{3} + 1$ $= 2^3x^3+1$

Take care of the exponents
$= 2^{3} = 8$ $=2^3=8$

Solution
$= 8 x^{3} + 1$ $=8x^3+1$

How do you factor (2x)^3 + 1(2x)3+1 (2x)^3 + 1?